Question descriptionSo, this is the balanced equation given
N2 + 3H2 => 2NH3
And we know that N2 is 28.0134g/mol
Given that there are 3L of NH3, how many Liters of N2 are needed?
PV=nRT (equation to be used)
P=1.0526atm
T=291.15K
R=0.08206 Latm/molK
V= 3L of NH3
V=?L of N2
What is ‘n’ and how do I find it? And then how do I find the Volume for the amount of N2 needed to create 3L of NH3?